A short instructional video by Ben demonstrating how to use a bar model to solve a word problem about a charity race. He models Cian and Hope's distances, divides the total (60 miles) into five equal parts (12 miles each), and computes that Hope ran 36 miles more than Cian by taking the difference (3 parts = 36 miles).
Questions this video answers
60 miles
12 miles
36 miles
Chapters
Hi, I'm Ben. And in this video, we're going to be looking at how we can use the bar model to solve more complex multiplication problems, where we do know some of the information. This is the question. Hope and Cian were running as a team in a charity race. Hope ran four times further than Keon. Together they ran 60 miles. How much further did Hope run than Keon? Let's represent this as a bar. So we have Cian, and we know that he ran some miles. We now have Hope, and we know that Hope ran four times the distance that Kian ran. So there we have our bar model. Let's go back to the question. It says that they ran 60 miles. So we can see that the total, the whole, is 60 miles, and it's made up of five parts. So we can look at 60 divided by 5, which gives us 12. Therefore, we know that each part is worth 12. The final stage is to go back to the question again. This is so important that the children keep coming back to the question. And it says, how much further did Hope run than Cian? So we can see here this is the difference. Kian. Hope ran these three more. So 12 plus 12 plus 12 or 12 multiplied by three, which is 36. So Hope ran 36 miles more than Keon. And that's how we use the bar model to solve more complex multiplication problems.